SOLUTION: the height h (in feet) above the ground of a stone tossed over a bridge is given by h= -16t^2+20t+160 , where t is the time (in seconds) since the stone was tossed. how long, to
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Question 964507: the height h (in feet) above the ground of a stone tossed over a bridge is given by h= -16t^2+20t+160 , where t is the time (in seconds) since the stone was tossed. how long, to the nearest hundredth of a second, will it take until the stone is at a height of 40 feet above the ground?
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
the height h (in feet) above the ground of a stone tossed over a bridge is given by h= -16t^2+20t+160 , where t is the time (in seconds) since the stone was tossed. how long, to the nearest hundredth of a second, will it take until the stone is at a height of 40 feet above the ground?
***
h= -16t^2+20t+160
40= -16t^2+20t+160
-16t^2+20t+120=0
divide by 4:
-4t^2+5t+30=0
solve for t by quadratic formula:
a=-4, b=5, c=30
ans:
t=3.43
how long will it take until the stone is at a height of 40 feet above the ground? 3.43 sec
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