SOLUTION: " If i have 2 nubers in a rational equation how do i solve it, 1/2x - 2/3 =-2 and 3/5x - 4 = 2/3x + 1 ?

Algebra ->  Algebra  -> Rational-functions -> SOLUTION: " If i have 2 nubers in a rational equation how do i solve it, 1/2x - 2/3 =-2 and 3/5x - 4 = 2/3x + 1 ?      Log On

Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

   


Question 94117: " If i have 2 nubers in a rational equation how do i solve it, 1/2x - 2/3 =-2 and 3/5x - 4 = 2/3x + 1 ?
Answer by ankor@dixie-net.com(12701) About Me  (Show Source):
You can put this solution on YOUR website!
1/2x - 2/3 =-2 and 3/5x - 4 = 2/3x + 1 ?
;
1%2F2x - 2%2F3 = - 2
:
First, we want to get rid of the denominators, multiply equation by 6 (2*3):
(6)1%2F2x - (6)2%2F3 = 6(-2)
:
Cancel out 2 and 3 and we end up with
3x - 2(2) = -12
3x - 4 = -12
:
Add 4 to both sides to isolate x
3x - 4 + 4 = -12 + 4
3x = -8
:
Divide both sides by 3
x = -8/3
:
:
3%2F5x - 4 = 2%2F3x + 1
:
Here, we get rid of the denominator by multiplying equation by 15 (3*5):
(15)3%2F5x - (15)4 = (15)2%2F3x + (15)1
:
3(3x) - 60 = 5(2x) + 15
9x - 60 = 10x + 15
:
Subtract 9x from both sides:
9x - 9x - 60 = 10x - 9x + 15
-60 = 1x + 15
:
Subtract 15 from both sides:
-60 - 15 = x + 15 - 15
-75 = x
:
Check both solutions by substituting for x in both original equations