SOLUTION: Q5 fit a second degree parabola to the following data: <pre> x 1 2 3 4 5 y 100 1200 1390 1625 1015</pre>

Algebra.Com
Question 935202: Q5 fit a second degree parabola to the following data:
 
x  1     2      3      4      5
y 100   1200   1390   1625   1015
Answer by Edwin McCravy(20060)   (Show Source): You can put this solution on YOUR website!
To get the closest fitting parabola, we use a TI-84 calculator:

Press WINDOW 

Make it read Xmin=-1, Xmax=7,Ascl=1,Ymin=-50,Xmax=1700,Yscl=100,

Press 2ND, Y=, ENTER, ENTER 

Press STAT, ENTER and enter x-values in L1 and y-values in L2

Press STAT, ->, 5  

Next to   "Store RegEQ:" Press VARS -> ENTER ENTER to get Y1 there

Scroll to "Calculate"

Press ENTER, GRAPH

See this



To see the equation, Press Y=

equation of best fitting parabola:



Edwin
RELATED QUESTIONS

Combine 

4         
---       -   x^(1/3)
x^(2/3)... (answered by jim_thompson5910)

Construct a scatterplot for the (x, y) values below, and answer the following questions.... (answered by Edwin McCravy)

ABCD is a square


       A _________________D
        
|\               /|
   (answered by greenestamps)

Simplify:


        
        ((x^(3/2))y^-3)^1/3
        --------------------
    (answered by jim_thompson5910)


The following is not a discrete probability distribution because 

 x... (answered by stanbon,Edwin McCravy)

can you tell me if my answer is correct.
determine the horizontal asymptotes of: 

 (answered by jim_thompson5910)



   x        3               
—————— = - ———
 2x-1... (answered by Edwin McCravy)


A random variable x has this probability distribution,  

x	0	   1	   2	    3... (answered by Edwin McCravy)

find Y give answer in the simplest form

                            
             (answered by Alan3354)