SOLUTION: (a) Graph the function f(x)= x^3 - 4
(b) Approximate to the nearest tenth, the real root of the equation
f(x)= x^3 - 4 = 0 please help me
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Question 92199This question is from textbook Algebra and Trigonometry
: (a) Graph the function f(x)= x^3 - 4
(b) Approximate to the nearest tenth, the real root of the equation
f(x)= x^3 - 4 = 0 please help me
This question is from textbook Algebra and Trigonometry
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
a) "Graph the function f(x)= x^3 - 4"
In order to graph , we need to plot some points.
We can start at any x value, so lets start at x=-2
Lets evaluate
Start with the given polynomial
Plug in
Raise -2 to the third power to get -8
Now combine like terms
So when ,
So our 1st point is (-2,-12)
----Now lets find another point----
Lets evaluate
Start with the given polynomial
Plug in
Raise -1 to the third power to get -1
Now combine like terms
So when ,
So our 2nd point is (-1,-5)
----Now lets find another point----
Lets evaluate
Start with the given polynomial
Plug in
Raise 0 to the third power to get 0
Remove any zero terms
So when ,
So our 3rd point is (0,-4)
----Now lets find another point----
Lets evaluate
Start with the given polynomial
Plug in
Raise 1 to the third power to get 1
Now combine like terms
So when ,
So our 4th point is (1,-3)
----Now lets find another point----
Lets evaluate
Start with the given polynomial
Plug in
Raise 2 to the third power to get 8
Now combine like terms
So when ,
So our 5th point is (2,4)
Now lets make a table of the values we have calculated
Now plot the points
Now connect the points to graph (note: the more points you plot, the easier it is to draw the graph)
b)
"approximate to the nearest tenth, the real root of the equation
f(x)= x^3 - 4 = 0 "
add 4 to both sides
Take the cube root of both sides
So the solution is approximately 1.5874010519682 which rounds to 1.6
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