SOLUTION: simplify (n^5+2n^4+3n^3)+n^3
i divided everything by the (n^3) and i came up with n^2+2n+4
but since it looks like an addition problem im not sure how to work it out.
Algebra.Com
Question 91125: simplify (n^5+2n^4+3n^3)+n^3
i divided everything by the (n^3) and i came up with n^2+2n+4
but since it looks like an addition problem im not sure how to work it out.
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
GOOD START BUT YOU NEED TO FINISH IT THUS:
(N^5+2N^4+3N^3)+N^3
N^5+2N^4+4N^3 NOW FACTORE OUT N^3.
N^3(N^2+2N+4) NOW FACTOR THE QUADRATIC EQUATION THUS:
N^3(N+2)(N+2) ANSWER.
RELATED QUESTIONS
Hi, would you tell me where I went wrong? My textbook answer should be -12 but I came up (answered by richard1234)
Factor n^4 - 2n^3 -... (answered by nerdybill)
(n^4-2n^3-3n^2+7n-2)/(n-2) (answered by stanbon)
Please help with this questions, prove by induction that the formulas positive integral... (answered by ikleyn)
In a math book I am using / reading the author states that the expression n + (n-3)... (answered by AlgebraLady88)
A word problem is expressed as 3(2n+1)=2(2n+3)+5.
This implies 6n+3=4n+6+5. The next... (answered by josgarithmetic,MathTherapy)
My question is how to solve the equation 2 - n = 7 - 2n. I've tried the following... (answered by checkley75)
I've been working through factoring polynomials and have solved the following as such;... (answered by stanbon)
9{[4(n-4)+17]-[3(2n-2)+5]}... (answered by Jc0110)