SOLUTION: Write an equation of the line in standard form that Satisfies the stated conditions
1) perpendicular to the line 3x-2y=6 at the point where it crosses the y axis.
2) parallel to
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Question 902881: Write an equation of the line in standard form that Satisfies the stated conditions
1) perpendicular to the line 3x-2y=6 at the point where it crosses the y axis.
2) parallel to the line 3x + 4y=6; passing through the x-intercept of the graph of the line x + 2y= 6
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
Number 2:
Any 3x+4y=c will be a parallel line to the first equation.
The x-intercept of , is , , .
This is the point (6,0).
You want 3x+4y=c to pass through or contain point (6,0).
.
The line you are looking for is .
Question Number 1:
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You should study what I showed for Number 2, and then solve Number 1 yourself.
In number 2, you wanted a line parallel to another. In Number 1 you want a line PERPENDICULAR to another. Either use some understanding of standard form, or convert the given first equation into slope-intercept form, and identify the slope. You want the product of the slopes to be . for lines to be perpendicular. Use the needed point to find the value for c in Ax+By=C, along with the needed values for A and B in the expression Ax+By.
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LESS WORDY WAY TO THINK OF THIS,
What is the slope?
You want to use slope of for the line you want.
NOW, known slope m, known given point, determine what is C.
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