SOLUTION: My book doesn't explain how to solve:
(3√-5)(-4√-12)
I'd like to know what to do with the radicands and understand this.
So far I thought it was: (3√-1√5
Algebra.Com
Question 895717: My book doesn't explain how to solve:
(3√-5)(-4√-12)
I'd like to know what to do with the radicands and understand this.
So far I thought it was: (3√-1√5)(-4√-1√12) to (3√5)(-4 •2√3) but it doesn't seem right at all and I got stuck. Please help, much thanks!!
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Those given factors contain imaginary numbers.
You would be using the idea, .
Here is the arithmetic.
Notice that although the original product shows imaginary numbers, the final result in this example is REAL.
The commutative property for multiplication was used freely where convenient.
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