Factor all numerators and denominators: Wow! On many of these type problems, several factors in numerators cancel with factors in denominators. But not this one! Only one of the (x+7)'s in the bottom of the first fraction cancels with the (x+7) in the top of the second fraction, and that's all the cancelling possible! And we end up with: Finally we make one fraction by indicating the multiplication of numerators and denominators: Just leave it like that. Edwin