SOLUTION: Solve the equation 2x^3-5x^2+x+2=0 given that 2 is a zero of f(x)= 2x^2-5x^2+x+2.

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Question 881027: Solve the equation 2x^3-5x^2+x+2=0 given that 2 is a zero of f(x)= 2x^2-5x^2+x+2.
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39620)   (Show Source): You can put this solution on YOUR website!
2 is a zero; perform synthetic division to find the other polynomial factor of the function:



____2_____|____2_____-5_____1_______2
__________|
__________|__________4_____-2______-2
__________|_____________________________
quotient____________2_____-1____-1______0

That resulting quotient means whose roots or zeros are

which are the other two roots for the original equation.
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
Solve the equation 2x^3-5x^2+x+2=0 given that 2 is a zero of f(x)= 2x^2-5x^2+x+2.


Factors of  are: (x - 2),(2x + 1), and (x - 1)

Therefore, solutions are:  

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