SOLUTION: x^3- 3x^2-4x+12=0
i have to solve for x
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Question 86809: x^3- 3x^2-4x+12=0
i have to solve for x
Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
x^3-3x^2-4x+12=0
x^2(x-3)-4(x-3)=0
(x^2-4)(x-3)=0
(x+2)(x-2)(x-3)=0
x+2=0
x=-2 answer.
x-2=0
x=2 answer.
x-3=0
x=3 answer.
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