SOLUTION: Given the quadratic equation, written in General/ vertex form, state/ discuss.. Y=3/4(x+2)^2-5 1) the vertex 2) opening up or down 3) wider or narrower comparing with y=x^

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Question 864540: Given the quadratic equation, written in General/ vertex form, state/ discuss..
Y=3/4(x+2)^2-5
1) the vertex
2) opening up or down
3) wider or narrower comparing with y=x^2
4)Domain and range
5) axis of symmetry

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi
Y=3/4(x+2)^2-5
1) the vertex (-2,-5)
2) opening up or down: 3/4> 0 Opening Up along x = -2
3) wider or narrower comparing with y=x^2
4)Domain and range: y ≥ 5, Domain: all real numbers
5) axis of symmetry x = -2


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