SOLUTION: 2/sqrt[3] + sqrt[2] Can you help me rationalize the denominator? I really apprecuate your help. It would help so much if you could show me how you do this.

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Question 86383This question is from textbook Intermediate Algebra
: 2/sqrt[3] + sqrt[2]
Can you help me rationalize the denominator? I really apprecuate your help. It would help so much if you could show me how you do this. This question is from textbook Intermediate Algebra

Found 2 solutions by stanbon, Edwin McCravy:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
2/sqrt[3] + sqrt[2]
---------
Multiply numerator and denominator by (sqrt3 - sqrt2) to get:
[2(sqrt3 - sqrt2)]/[3-2]
=2(sqrt3 - sqrt2)
=======================
Why does this work?
Because (sqrt3+sqrt2)(sqrt3-sqrt2) = 3+sqrt6-sqrt6-2 = 3-2=1
===============
Cheers,
Stan H.
Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!

Can you help me rationalize the denominator? I really apprecuate your help. It
would help so much if you could show me how you do this.

Form the conjugate surd of the denominator:
1. Copy the first term
2. Copy the second term with the sign changed.

The conjugate surd of the denominator  is
.  Write it over itself to form a 
fraction equal to 1:



Multiply the original eqpression by that fraction.  It doesn't
change the value because the fraction equals 1.

    
×



FOIL out the denominator:



Cancel the terms in  in the bottom







You can multiply that out if you like and get



Edwin
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