SOLUTION: Give the locations of horizontal and vertical asymptotes and the x-coordinate of holes. y = {{{ (2x^3 + 2)/(x^2

SOLUTION: Give the locations of horizontal and vertical asymptotes and the x-coordinate of holes. y = {{{ (2x^3 + 2)/(x^2 - 9) }}}

Question 860506: Give the locations of horizontal and vertical asymptotes and the x-coordinate of holes.
y =

Answer by josgarithmetic(39626) (Show Source): You can put this solution on YOUR website!
No holes, but two vertical asymptotes.

Doing division you get y=2x+some remainder, and the remainder becomes increasingly small as x gets extreme to either left or right. The slant asymptote is . I do not show this polynomial division, so ask for it if you need to see it.

The denominator is ; so vertical asymptotes are at and .
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