SOLUTION: i am trying to solve the problem of x/(x^2-9) 1/(x 3)=4 i started by using an LCD of (x 3)(x-3) to multiply to each term on both sides of equation. I arrived at an answer of x

Question 844070: i am trying to solve the problem of x/(x^2-9) 1/(x 3)=4
i started by using an LCD of (x 3)(x-3) to multiply to each term on both sides of equation. I arrived at an answer of x (x-3)=4(x^2-9). then i simplfied more to arrive at -4x^2-2x-33=0. i'm stuck. not sure how to tackle problem further
Found 2 solutions by Fombitz, nanakwame:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!

You have a sign error in your constant term and your x term,
Use the quadratic formula,

Answer by nanakwame(5) (Show Source): You can put this solution on YOUR website!
you made a mistake when grouping because you will get x (x-3)=4x^2-36
2x-3=4x^2-36
both the 2x and -3 will cross the equal sign and you will get
4x^2-2x-33=0
use the general formula and you will get -3.133 and 3.133

RELATED QUESTIONS
I�m supposed to solve the below expression for X, but I can�t figure out what I�m doing... (answered by jim_thompson5910)
I am trying to solve this equation: 3/x - 2/(x+1)=4/x I know I need to get the LCD and... (answered by scott8148)
Hi. Thank you so much for the help you have given me thus far,but I need help with this... (answered by josgarithmetic)
i worked this problem: (2x + 1)/3 - (3-x)/4 = (x)/6 and i got 1.67 = x which is wrong (answered by jrfrunner)
I am not sure how to do this problem: 1/2+2/3=x/6 do i find the lcd and multiply that... (answered by rfer)
11/12-x/4=x/3+5/6 I know I have to find the LCD but I am not sure which numbers I... (answered by amarjeeth123,MathTherapy)
I am trying to help my daughter solve the below problem: 2/3 x + 3 = 1/4 x... (answered by Alan3354)
I am trying to solve the equation: (1/(x-3))+(1/(x+3))=(10/(x^2-9)) Thanks in... (answered by ankor@dixie-net.com)
Good Morning, I am trying to solve the following equations x2 - 2x - 13 = 0 i am not... (answered by nerdybill,Theo)