SOLUTION: Write the expression LOGa(y+5)+2LOGa(x=1) as one logarithm.
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Question 82643This question is from textbook
: Write the expression LOGa(y+5)+2LOGa(x=1) as one logarithm.
This question is from textbook
Found 2 solutions by stanbon, jim_thompson5910:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Write the expression LOGa(y+5)+2LOGa(x+1) as one logarithm
loga[(y+5)(x+1)^2]
==============
Cheers,
Stan H.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given expression
+\log_a({x+1})^{2})
Use the identity =\log_a({x})^{y})
to move the 2 to the exponent
+\log_a({x^2+2x+1}))
Foil
(x^2+2x+1))
Combine the logs using this identity +\log_a({y})=\log_a({xy}))
)
Multiply the terms out
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