SOLUTION: Multiply
(n^2+3n-4)/(n^2-16)*(n^2+3n-4)/(n^2-1)
Please I need help with this exercise! Thank you!
Algebra.Com
Question 825868: Multiply
(n^2+3n-4)/(n^2-16)*(n^2+3n-4)/(n^2-1)
Please I need help with this exercise! Thank you!
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
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Everything will factor, the denominators are "difference of squares"
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Cancel (n+4) and (n-1) leaving
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