SOLUTION: 2.A solution containing 30% acid is to be mixed with a solution containing 50% acid to make 200L of a solution containing 40% acid. How much of each solution should be used?
Then
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Question 82504This question is from textbook Algebra 1
: 2.A solution containing 30% acid is to be mixed with a solution containing 50% acid to make 200L of a solution containing 40% acid. How much of each solution should be used?
Then there is a chart to put the work into
This question is from textbook Algebra 1
Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
.3x+.5(200-x)=.4*200
.3x+100-.5x=80
-.2x=-20
x=-20/-.2
x=100 answer for the 30% acid solution.
200-100=100 is the answer for the 50% solution also.
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