SOLUTION: {{{i^1= i}}} {{{ i^5 = i}}}
{{{i^2= -1 }}} {{{ i^6 = -1}}}
{{{i^3= -i }}} {{{ i^7= -i}}}
{{{i^4= 1 }}} {{{ i^8 = 1}}}
I am supposed to use the above pa
Algebra.Com
Question 79349:
I am supposed to use the above pattern to simplify the powers of i.
Please help
Please help
Found 2 solutions by chitra, josmiceli:
Answer by chitra(359) (Show Source): You can put this solution on YOUR website!
Here we are given the values of i till = 1
Now to find this can be written as:
This can be written as:
Lets now find the value of from the given data:
= 1
=
=
= i
=
= i * i
=
= -1
Similarly the rest are also found out.
= -i
= 1
= i
Thus the value of = i
And we know that = i
Thus, =
=
= i
Hence, the solution.
----------------------------------
----------------------------------
2nd method
Or we can also find the value of =
=
=
= i
Now 65 = 13 * 5
=
=
= i
Hence, the solution.
Regards
Chitra
Online MAth tutor
www.knowledgeonlineservices.com
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
The easiest property to make use of is
because every time you
multiply it times itself, you still get 1
Remember you ADD the exponents in each case, so
Think of as multiplied times itself a certain
number of times and multiply that by whatever factor is left over
and 1 remainder
What you've got is or
So, answer
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