SOLUTION: {{{ sqrt (6x+7) }}} - {{{ sqrt (3x+3) }}} = 1 I am supposed to solve the radical equations for the variable. I started out by thinking I should separate each of the numbers and

Question 77195This question is from textbook
: - = 1
I am supposed to solve the radical equations for the variable. I started out by thinking I should separate each of the numbers and factor as best I could. So then I had:
* + 7 - + = 1
After that, I didn't think that the could cancel each other out because then there would be no variable, so I am currently stuck right there. I would be really grateful if you let me know if I am on the right track, or if I am really off, help me get on track. Thank you. This question is from textbook

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
sqrt (6x+7) - sqrt (3x+3) = 1
Square it the way it is so you end up with just one new radical:
Result of square both sides is:
6x+7 -2sqrt[(6x+7)(3x+3)] + 3x+3 = 1
Isolate the remaining radical:
9x+10 - 2[....] = 1
2[....]= 9x+9
Square to get rid of the radical:
-----
4[(6x+7)(3x+3) = [9(x+1)]^2
Now, solve for x.
I'll leave that to you.
Cheers,
Stan H.

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