SOLUTION: Can someone Please help me solve this problem, Thank You very much!!! Write the terms of the series and find their sum.*In the problem the 4 is above the Σ and the k=1 is b

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Question 764816: Can someone Please help me solve this problem, Thank You very much!!!
Write the terms of the series and find their sum.*In the problem the 4 is above the Σ and the k=1 is below it*
4Σk=1 (k+9)^2
The terms of the series are ___ ( use a comma to separate the answers as needed.)
4Σk=1 (k+9)^2=___

Answer by ramkikk66(644)   (Show Source): You can put this solution on YOUR website!

4Σk=1 (k+9)^2

The expression should be read as (k = 1 through 4, sigma (k+9)^2)

Sigma means that you should add the terms.

How many terms? K ranges from 1 to 4, so there are 4 terms (K=1, k =2, k=3,k=4)

What are the terms? To get the first term, you substitute k = 1 in the given
expression. To get the second term, you substitute k = 2 and so on.

The given expression is (k + 9)^2

1st term = (1 + 9)^2 = 10^2 = 100
2nd term = (2 + 9)^2 = 11^2 = 121
3rd term = (3 + 9)^2 = 12^2 = ... you get the idea.

Find the 4 terms, and just add them to get the answer.

Hope this helps :) Let me know if it's not clear.


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