SOLUTION: Find the perimeter of triangle ABC, with coordinates A(-3, 0), B(0, 4), and C(3, 0)

Question 758150: Find the perimeter of triangle ABC, with coordinates A(-3, 0), B(0, 4), and C(3, 0)
Found 2 solutions by Cromlix, MathTherapy:
Answer by Cromlix(4381) (Show Source): You can put this solution on YOUR website!
using the formula: square root of (x2 - x1)^2 + (y2 - y1)^2
AB (0-(-3))^2 + (4 - 0)^2
= 9 + 16
= 25
Square root = 5
BC (3 - 0)^2 + (0 - 4)6"
= 9 + 16
= 25
Square root = 5
AC (3 - (-3)^2 + (0 - 0)^2
81
Square root = 9
Size of AB - 5
Size of BC - 5
Size of AC - 9
Perimeter = 23 units
Hope this helps
:-)
Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!

Find the perimeter of triangle ABC, with coordinates A(-3, 0), B(0, 4), and C(3, 0)

Using distance formula: , you will get AB = 5 units, and BC = 5 units.

Since A and C have the same y-coordinate (0), these two points will be on the x-axis where all y-values are 0. Therefore, AC will have a length of 3 - - 3, or 6 units.

Perimeter = 5 + 5 + 6, or units
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