SOLUTION: Find the x- and y-intercepts. If no x-intercepts exist, state so.
f(x) = 3x2 + 6x + 1
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Question 736770: Find the x- and y-intercepts. If no x-intercepts exist, state so.
f(x) = 3x2 + 6x + 1
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
f(x) = 3x2 + 6x + 1
On X axis y=0
3x^2+6x+1=0
Find the roots of the equation by quadratic formula
a= 3 b= 6 c= 1
b^2-4ac= 36 - 12
b^2-4ac= 24 = 4.9
x1=( -6 + 4.9 )/ 6
x1= -0.18
x2=( -6 -4.9 ) / 6
x2= -1.82
Intersection at -0.18 and -1.82
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