SOLUTION: find the y-k=a(x-h)^2 equation for the parabola with vertex = (-2,6) and y-intercept = -2

Question 731342: find the y-k=a(x-h)^2 equation for the parabola with vertex = (-2,6) and y-intercept = -2
Found 2 solutions by josgarithmetic, MathLover1:
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
Each of those points gives you a specific equation, so you could have two of them.

will be our best form to start with (my convenience only).

Point (-2, 6):

and since the point is also the vertex,

.

That point being vertex lets us find , so now we only have one unknown variable in the equation other than the general (x, y) variables.

The other given point is (0, -2):

Equation for the parabola is
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
given:
vertex = (,) and
Step 1:
The standard equation of parabola when the vertex is along intercept is given by:
where vertex:(,) = (,)
and
Step 2:
Putting values of , and in the standard equation and simplifying you get:

is the required equation of parabola.This is the answer.

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