SOLUTION: If y varies directly as the square root of x, and y=12 when x=4, find y when x=100.

Question 726256: If y varies directly as the square root of x, and y=12 when x=4, find y when x=100.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
If y varies directly as the square root of x,
y = k*sqrt(x)
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Solve for "k" using "y=12 when x=4"
12 = k*sqrt(4)
k = 6
------
Equation:
y = 6*sqrt(x)
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find y when x=100.
y = 6*sqrt(100)
y = 6*10
y = 60
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Cheers,
Stan H.
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