SOLUTION: How can I solve h^2-15h+50/h>0?

Question 666996: How can I solve h^2-15h+50/h>0?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

Set the numerator equal to zero and find the zeros of the function.

Using the zeros of the function, of which there will be two because the numerator is a factorable quadratic, and the point of discontinuity, i.e. the location of the vertical asymptote, plot four intervals on the

-axis. Namely -infinity to the value excluded from the domain, the the value excluded from the domain to the smaller zero, the smaller zero to the larger zero, and the larger zero to infinity. Note that all of these intervals are open-ended because your inequality is 'strictly less than', i.e. "<" as opposed to less than or equal,

.

Select a value from each of the four intervals that is NOT an endpoint. Evaluate your function for each of your selected values. You will get two positive values and two negative values. The union of the two intervals where you obtained negative values is the solution set of the given inequality.

Use a graphing program or your graphing calculator to graph the function. The above process will then make visual sense.

John

My calculator said it, I believe it, that settles it

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