SOLUTION: Alright, my past questions indicate that the equation is a rational equation. It's actually a radiacal equation. So heres the question: Find all real solutions in this equation:

Question 661045: Alright, my past questions indicate that the equation is a rational equation. It's actually a radiacal equation. So heres the question:
Find all real solutions in this equation:
√(x-3)+1=√(x+2)
Please answer immediately, I really need your help since I need it tomorrow! Thanks!
Found 2 solutions by MathLover1, ewatrrr:
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!

...raise both sides to power of

...raise both sides to power of

.. both sides divide by

check:

Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

Hi,
√(x-3)+1=√(x+2) || Squaring boths sides of the EQ
(√(x-3)+1)(√(x-3)+1) = x+2
x-3 + 2√(x-3)+ 1 = x+2
2√(x-3) = 4
√(x-3) = 2 || Squaring boths sides of the EQ
x-3 = 4
x = 7
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