SOLUTION: 5x/x^2-x-6 - 4/x^2+4x+4
How do you factor this problem out step by step?
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Question 64574This question is from textbook PRENTICE HALL MATHMATICS ALGEBRA 2
: 5x/x^2-x-6 - 4/x^2+4x+4
How do you factor this problem out step by step?
This question is from textbook PRENTICE HALL MATHMATICS ALGEBRA 2
Found 2 solutions by 303795, FadelSalem:
Answer by 303795(602) (Show Source): You can put this solution on YOUR website!
Factorise the expressions on the bottom of the fractions.
The common factor on the bottom will be (x-3)(x+2)(x+2). Multiply the first term by (x+2)/(x+2). Multiply the second term by (x-3)/(x-3). This will rewrite both terms so they are over the common denominator.
Multiply out the top parts of the problem
Rewrite over the common denominator
Answer by FadelSalem(12) (Show Source): You can put this solution on YOUR website!
5x/x^2-x-6 - 4/x^2+4x+4 =
5x/(x-3)(x+2) - 4/(x+2)^2 =
5x(x+2)/(x-3)(x+2)^2 - 4(x-3)/(x-3)(x+2)^2 =
(5x^2+10x)/(x-3)(x+2)^2 + (-4x + 12)/(x-3)(x+2)^2 =
(5x^2 + 6x + 12)/(x-3)(x+2)^2
Happy New Year
Fadel Salem
Egypt
fadelsalem@hotmail.com
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