SOLUTION: i need to find the vertical asymptotes of {{{4x^2+9/9x^2+1}}}
i don't know what to do after i get to this part {{{x= sqrt(-1/9)}}}
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Question 636236: i need to find the vertical asymptotes of
i don't know what to do after i get to this part
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
\ =\ 4x^2\ +\ \frac{9}{9x^2}\ +\ 1\ )
has a vertical asymptote at 
, in other words the 
-axis, because that is where the denominator of the rational part of the function goes to zero.
However, I rather suspect that you really meant:
\ =\ \frac{4x^2\ +\ 9}{9x^2\ +\ 1})
which has no real number zeros for the denominator polynomial, and therefore has no vertical asymptotes.
John
My calculator said it, I believe it, that settles it
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