SOLUTION: Find the maximum y value on the graph of y=f(x)
f(x)=-x^2+8x+1
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Question 630632: Find the maximum y value on the graph of y=f(x)
f(x)=-x^2+8x+1
Found 2 solutions by reviewermath, stanbon:
Answer by reviewermath(1029) (Show Source): You can put this solution on YOUR website!
The x-coordinate of the vertex is and the y-coordinate is . Since a < 0, y = f(x) has a maximum value. The maximum value is .
The graph is
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find the maximum y value on the graph of y=f(x)
f(x)=-x^2+8x+1
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Max occures when x = -b/(2a) = -8/(2*-1) = 4
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Max y-value = f(4) = -4^2+8*4+1 = -16 + 32 + 1 = 17
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Cheers,
Stan H.
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