SOLUTION: Solve using the elimination method. Show your work. If the system has no solution or an infinate number of soluttions state this.
10x+5y-52.5
30x-7y=80.5
Algebra.Com
Question 626558: Solve using the elimination method. Show your work. If the system has no solution or an infinate number of soluttions state this.
10x+5y-52.5
30x-7y=80.5
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Solve using the elimination method. Show your work.
If the system has no solution or an infinite number of solutions state this.
10x + 5y = 52.5
30x - 7y = 80.5
:
Multiply the 1st equation by 3
30x + 15y = 157.5
30x - 7y = 80.5
-------------------subtraction eliminates x, find y
0 + 8y = 238
y =
y = 29.75
:
Find x using the 1st equation, y = 29.75
10x + 5(29.75) = 52.5
10x + 148.75 = 52.5
10x = 52.5 - 148.75
10x = 96.25
x =
x = 9.625
:
Check solutions in the 2nd equation
30(9.625) - 7(29.75) = 80.5
288.75 - 208.25 = 80.5; confirms our solution of x=9.625, y=29.75
RELATED QUESTIONS
solve using the elimination method. show your work if the system has no solution or an... (answered by solver91311)
Solve using the elimination method. Show your work. If the system has no solution or an... (answered by richwmiller)
Solve using the elimination method. Show your work. If the system has no solution or an... (answered by neatmath)
Solve using the elimination method. Show your work. If the system has no solution or an... (answered by mananth,Math-Help)
Solve using the elimination method. Show your work. If the system has no solution or an... (answered by edjones)
Solve using the elimination method. Show your work. If the system has no solution or an... (answered by edjones)
Solve using the elimination method. Show your work. If the system has no solution or an... (answered by ewatrrr)
Solve using the elimination method. Show your work. If the system has no solution or an... (answered by jim_thompson5910)
. Solve using the elimination method. Show your work. If the system has no solution or an (answered by Alan3354)