x-1 x ————— + —————— x³ x²+1
x-1 x ————— + —————— x³ x²+1 The LCD is x³(x²+1), so we multiply each fraction by whichever factor of the LCD its denominator is lacking, over itself. The first fraction's denominator lacks the factor x²+1 and the second fraction's denominator lacks the factor x³, so we put the missing factors over themselves and multiply, so that the denominators will both become the LCD. x-1 x²+1 x x³ ————— · —————— + —————— · ———— x³ x²+1 x²+1 x³ (x-1)(x²+1) (x)(x³) ——————————— + ———————————— x³(x²+1) (x²+1)(x³) x³+x-x²-1 x4 ——————————— + ———————————— x³(x²+1) (x²+1)(x³) x³+x-x²-1+x4 —————————————— x³(x²+1) x4+x³-x²+x-1 —————————————— x³(x²+1) Edwin
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