SOLUTION: write the equation of the circle in standard form. Find the center, radius, intercepts and graph the circle. x^2+y^2-10x-4y+13=0

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Question 622801: write the equation of the circle in standard form. Find the center, radius, intercepts and graph the circle.
x^2+y^2-10x-4y+13=0

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi, re Ty, Kudos to You, Spectacular!!! Keep Posting!!
x^2+y^2-10x-4y+13=0
x^2+y^2-10x-4y = -13
(x-5)^2 + (y-2)^2 = -13 + 25 + 4
C(5,2), r = 4 and
y = 0 ⇒ ⇒ x = 5 ±


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