# SOLUTION: please help!! I have been working on this and can't get an answer. "A model of the daily profits "p"of a gas station based on the price per gallon "g" is: p=-15000g^2 + 34500g

Algebra ->  Algebra  -> Rational-functions -> SOLUTION: please help!! I have been working on this and can't get an answer. "A model of the daily profits "p"of a gas station based on the price per gallon "g" is: p=-15000g^2 + 34500g      Log On

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 Algebra: Rational Functions, analyzing and graphing Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Rational-functions Question 617036: please help!! I have been working on this and can't get an answer. "A model of the daily profits "p"of a gas station based on the price per gallon "g" is: p=-15000g^2 + 34500g-16800. Use the discriminant to find if the station can profit \$4000 per day. Explain" Thanks so much for the help!! Answer by Alan3354(30978)   (Show Source): You can put this solution on YOUR website!"A model of the daily profits "p"of a gas station based on the price per gallon "g" is: p=-15000g^2 + 34500g-16800. Use the discriminant to find if the station can profit \$4000 per day. Explain" ------------ p=-15000g^2 + 34500g-16800 Disc = b^2 - 4ac = 34500^2 - 4*15000*16800 Disc = 182250000 ----------------- The discriminant is +, meaning there are 2 values of g that give p=0, or break even. The Disc doesn't directly answer the question. "Use the discriminant" makes no sense. ----- Find the max of the function. It's a parabola, so the max is at the vertex The vertex is on the LOS, the Line of Symmetry, or Axis of Symmetry The eqn of the LOS is g = -b/2a = -34500/2*-15000 LOS is g = 1.15 ---- Find p at g = 1.15 p = -15000*1.15^2 + 34500*1.15 - 16800 p = \$3037.50 ----------- That's the max profit per day using that function.