SOLUTION: Find the x and y intercepts f(x)= 4x^2 +12x +9
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Question 609149
:
Find the x and y intercepts
f(x)= 4x^2 +12x +9
Found 2 solutions by
flame8855, ewatrrr
:
Answer by
flame8855(424)
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xintercept y=0
4x^2+12x+9=0
(2x+3)^2 = 0
x=-3/2
(-3/2,0)
yintercept x=0
y=0
(0,9)
Answer by
ewatrrr(24785)
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Hi
f(x)= 4x^2 +12x +9
f(x)= 4(x+3/2)^2 0
f(x)= 4(x+3/2)^2
(x+3/2)^2 = 0 x = -3/2
x = 0, then y = 9
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