SOLUTION: I need to find the oblique asymptote for (x^3-9x)/(x^2+x-20)

Question 607041: I need to find the oblique asymptote for (x^3-9x)/(x^2+x-20)
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
I need to find the oblique asymptote for (x^3-9x)/(x^2+x-20)
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When degree of numerator is one higher than that of the denominator, you will have an oblique asymptote.
To find the oblique asymptote, divide numerator by denominator.(by long division)
........................x..... -1.............................
....x^2+x-20 ) x^3 +0.... +9x .......................
........................x^3 +x^2-20x..................................
...............................-x^2-11x..........................
...............................-x^2 -x+20..........................
..................................... -10x-20..................
You will get an answer=(x-1)+remainder(10x-20)
Equation of oblique asymptote: y=x-1
see graph below:
..

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