SOLUTION: why isn't (1,3) (2,2) (1,5) (2,6) a function

Question 592852: why isn't (1,3) (2,2) (1,5) (2,6) a function
Found 2 solutions by jim_thompson5910, lwsshak3:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Because the x value of x = 1 maps to both y = 3 and y = 5 at the same time. You can't have an input map to two different outputs in order to have a function.
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
why isn't (1,3) (2,2) (1,5) (2,6) a function
For an expression to be a function, for each x there must only be only one y.
You will note that for points (1,3) and (1,5), x has two different values y.
Similarly, (2,2 and (2,6) show the same. Therefore, these points are not from a function.
If you graph these points, you will get a curve similar to a parabola opening rightwards and it would fail the vertical line test which allows only one intersection for a function.
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