SOLUTION: How would you solve... ((1/x)^2-(x)^2)/((1/x)+(x))=(3/2) When i tried solving it i got stuck when trying to factor it. do not know what to do when there is an (x^40) Please help

Question 580191: How would you solve... ((1/x)^2-(x)^2)/((1/x)+(x))=(3/2)
When i tried solving it i got stuck when trying to factor it. do not know what to do when there is an (x^40) Please help! thank you :)
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
if m is 1/x, you then have (m^2 - x^2) / (m + x) = 3/2

factoring ___ [(m + x)(m - x)] / (m + x) = 3/2 ___ m - x = 3/2

replacing m ___ (2/x) - 2x = 3

multiplying by x ___ 2 - 2x^2 = 3x ___ 0 = 2x^2 + 3x - 2

factoring ___ 0 = (2x - 1)(x + 2)
RELATED QUESTIONS
how would you solve ((1/x)-(x/2))((2/x)-(x))=(1/2) When i tried to solve it i got... (answered by unlockmath)

(1/3)^x=(81)(9^(x-1)) when solving for x is -2/3. I do not know... (answered by lwsshak3)

How do I simplify: 1/(x-3) - 1/(x+3) - 1/(x-1) + 1/(x+1) I tried but i got stuck and... (answered by MathLover1)

Please help me solve and check this equation: 3x-7=6x-3(x+2) . I tried solving it and got (answered by jim_thompson5910,edjones)

I am trying to solve the quadratic equation 3x-12. When I factor out the binomial I get... (answered by richwmiller)

how do you solve this ?: 5/6X - 1/3 = 5/12 I tried solving it and got down to the final (answered by rfer)

1/x + 2/x = 6 It asks that i solve the equation. I got it down to 3/x = 6 and that... (answered by Mathtut)

I am trying to figure out how to simplify and hence solve the following equation.... (answered by khwang)

Good afternoon, Can someone please help me solve this question? Thank you in advance... (answered by Fombitz)