SOLUTION: If one side of a square is increased by 4 feet and an adjacent side is decreased by two feet,a rectangle is formed whose area is 12 square feet more than the area of the original s

Question 549119: If one side of a square is increased by 4 feet and an adjacent side is decreased by two feet,a rectangle is formed whose area is 12 square feet more than the area of the original square.Find the length of a side of the square.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
If one side of a square is increased by 4 feet and an adjacent side is decreased by two feet, a rectangle is formed whose area is 12 square feet more than the area of the original square.Find the length of a side of the square.
:
Let x = the side of the original square
and
x^2 = area of the square
then
(x+4) = new length of the rectangle
and
(x-2) = new width
then the area of the rectangle
(x+4)*(x-2) = x^2 - 2x + 4x - 8 = x^2+2x-8
;
"a rectangle is formed whose area is 12 square feet more than the area of the original square."
x^2 + x - 8 - x^2 = 12
2x = 12 + 8
2x = 20
x = 10 ft is the side of the original square
:
:
:
See if this checks out
(14*8) - (10*10) =
112 - 100 = 12
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