SOLUTION: What is the highest possible price for a bottle of the beer if it has to be under $4 and its price in cents is gotten by multiplying the number of cents by 4, its number of dollars

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Question 545822: What is the highest possible price for a bottle of the beer if it has to be under $4 and its price in cents is gotten by multiplying the number of cents by 4, its number of dollars by 3, and adding the two results?
Answer by Edwin McCravy(20060)   (Show Source): You can put this solution on YOUR website!
What is the highest possible price for a bottle of the beer if it has to be
under $4 and its price in cents is gotten by multiplying the number of cents by
4, its number of dollars by 3, and adding the two results?
The number of dollars has to be 3 for the beer to be under $4.

Let C = the number of cents

4×(the number of cents) + 3×(the number of dollars) < 400

4×C + 3×3 < 400

   4C + 9 < 400

Subtract 9 from both sides

       4C < 391

Divide both sides by 4

        C < 97.75

We must have a whole number of cents, so the
largest whole number of cents possible is 97.

So the highest possible price for the beer is 

4×97 + 3×3 = 388 + 9 = 397 cents which is $3.97

Edwin
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