SOLUTION: Can these be done? 3x^2 + 15x + 18 = 0 1 + 3y/y-2 = 6/y-2

Question 53222: Can these be done?
3x^2 + 15x + 18 = 0
1 + 3y/y-2 = 6/y-2
Answer by rchill(405) (Show Source): You can put this solution on YOUR website!
Use the "ac" method. Given an equation in the format where , then in our case. Now we need to find two numbers that when multiplied together is 54 and when added together is 'b' in the equation above, or 15 for us. Make a table of the numbers: 2*27=54, but 2+27=29; 3*18=54, but 3+18=21; 6*9=54 and 6+9=15 --> we found them! So, with the 6 and 9, we use them as coefficients and break up 'bx', thusly: . Now use grouping: . Now factor the two groupings: . The factor (x+2) is common now and we can factor that out to get . That means that either x+2=0 or 3x+9=0. Solving both of them shows us that x=-2 or x=-3.
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