Question 527124: Hey, I've been looking all over the internet for a way to convert (y=(m)x+b) into point-slope form. I can't remember though whether this only applies to quadratic equations. If you consider this two questions, my apologies, I'm new to this.
Thanks.
Found 2 solutions by jim_thompson5910, scott8148:
Answer by jim_thompson5910(35256)   (Show Source):
You can put this solution on YOUR website! Point slope form is
y - y1 = m(x - x1)
where (x1, y1) is a point that lies on the graph and m is the slope
From y = mx+b, the slope will be given. It'll be up to you find a point that lies on the graph. The easiest point is the y-intercept, which is (0, b). So x1 = 0 and y1 = b
This means that
y = mx+b
converts to
y - b = m(x - 0)
where y1 = b
If you need more help, email me at jim_thompson5910@hotmail.com
Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you
Jim
Answer by scott8148(6628)  (Show Source):
| |
|
