SOLUTION: Find the domain of the function algebraically: f(x) = (x^2+ 4)^1/2

Question 52469: Find the domain of the function algebraically:
f(x) = (x^2+ 4)^1/2
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
You are probably aware that you can't take the square root of a negative number and get a real number solution. So the domain of even roots can be found by setting the inside of the root>=0.
x^2+4>=0
x^2+4-4>=0-4
x^2>=-4
sqrt(x^2)>=sqrt(-4)
Only you can't take the square root of a negative number, so there is no number that x can't be.
The domain is all real numbers.
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