SOLUTION: i am pretty confused, can you help me with solving this problem and show me how its done:
y/(y^2-4^2)- 1/(y-2)
Algebra.Com
Question 524660: i am pretty confused, can you help me with solving this problem and show me how its done:
y/(y^2-4^2)- 1/(y-2)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
y/(y^2-4^2)- 1/(y-2)
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Factor:
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[y/(y-4)(y+4)] - [1/(y-2)]
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least common denominator: (y-2)(y+4)(y-4)
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Rewrite each fraction with the lcd as its denominator:
[y(y-2)]/lcd - (y-4)(y+4)/lcd
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Combine the numerators over the lcd
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[y^2-2y -[y^2-16]]/lcd
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= [16-2y]/[(y-2)(y^2-16)]
===========================
Cheers,
Stan H.
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