SOLUTION: c-2(x+5)^2+10.

Question 524446: c-2(x+5)^2+10.
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
My question is dealing with Graphing Quadratic Functions.
The problem is f(x)=xsquared -5.
**
y=x^2-5
you can look at this equation in different ways but one way is to see this equation as a standard form for a parabola: y=A(x-h)^2+k, with (h,k) being the (x,y) coordinates of the center.
For given equation: y=x^2-5
Vertex is at (0,-5)
To get more points plug in values of x.
But another way is to find x-intercepts:
x^2-5=0
x=�√5≈�2.24
You now have 3 points with which to plot the graph.
RELATED QUESTIONS
2/5 + c = 9/10 -... (answered by vheroli)

X/2+5=10 (answered by ewatrrr)

X\2... (answered by ewatrrr)

X/2-5=10 (answered by Fombitz)

c+1/c-5 /... (answered by mananth)

X-2(x+5)=10 (answered by algebrahouse.com)

10-38 c) solve for x and show all work. 3/10 + 2x/5 =... (answered by ewatrrr)

5. If f(x) = x^2 + 6, find f(�2). a) 4 b) 2 c) �2 d)... (answered by jim_thompson5910)

x/2+10=2/5(x+3o) (answered by lynnlo)