SOLUTION: x^2+4x+7=0 find all real solutions and express in a+bi

Question 52395: x^2+4x+7=0 find all real solutions and express in a+bi
Answer by Nate(3500) (Show Source): You can put this solution on YOUR website!
x^2 + 4x + 7 = 0
x^2 + 4x = -7
(x + 2)^2 = 4 - 7 = -3
x + 2 = +- sqrt(3)i
x = -2 +- sqrt(3)i

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

The discriminant -12 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.

In the field of imaginary numbers, the square root of -12 is + or - .

The solution is

Here's your graph:

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