SOLUTION: How do you graph the equation (x+1/2)^2+ (y-1/3)^2=1
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Question 52381: How do you graph the equation (x+1/2)^2+ (y-1/3)^2=1
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
This is the equation of a circle.
is the equation of a circle with center at (h,k) and of radius 1.
In this case is a circle with center at (, ) and radius 1.
R^2 at SCC
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