SOLUTION: I would appreciate help. thanks so much.
I have to solve by any method.
#1 x + 5y = 1 and x + 2y = -2
#2 3x + 5y = 9 and 2x + 5y = 6
Algebra.Com
Question 508561: I would appreciate help. thanks so much.
I have to solve by any method.
#1 x + 5y = 1 and x + 2y = -2
#2 3x + 5y = 9 and 2x + 5y = 6
Found 2 solutions by Alan3354, stanbon:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
x + 5y = 1
x + 2y = -2
------------ Subtract
3y = 3
y = 1
------
x = -4
================
3x + 5y = 9
2x + 5y = 6
------------ Subtract, etc, same as #1
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
to solve by any method.
#1 x + 5y = 1
x + 2y = -2
---
Subtract and solve for "y":
3y = 3
y = 1
---
Solve for "x":
x + 2y = -2
x + 2*1 = -2
x + 2 = -2
x = -4
----------------------------------------------
#2 3x + 5y = 9
2x + 5y = 6
---
Subtract and solve for "x":
x = 3
---
Solve for "y":
2x + 5y = 6
2*3 + 5y = 6
6 + 5y = 6
5y = 0
y = 0
----------------------------------------------
Cheers,
Stan H.
==============================================
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