SOLUTION: How do I solve these by elimination or substitution? #1 y = -1 and x = 2 #2 y = 1/2 x + 2 and y = 2x-1

Question 507280: How do I solve these by elimination or substitution?
#1 y = -1 and x = 2
#2 y = 1/2 x + 2 and y = 2x-1
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How do I solve these by elimination or substitution?
#1 y = -1 and x = 2
Solution: (2,-1)
---------------------------
#2 y = 1/2 x + 2 and y = 2x-1
Substitution:
(1/2)x+2 = 2x-1
---
Subtract (1/2)x from both sides to get:
(3/2)x = 3
(1/2)x = 1
x = 2
---
Solve for "y":
y = (1/2)x+2
y = (1/2)2 + 2
y = 1 + 2
y = 3
============
Cheers,
Stan H.
============
RELATED QUESTIONS
-x+y=1 2x+y=-2 Solve using substitution method and elimination... (answered by iamverybadinmath)

Solve the system by graphing, substitution, or elimination. 1. Y=2 Y=x^2-14 2.... (answered by Alan3354)

I need to know how to solve these equations using substitution thanks:) -x+y=7 and... (answered by stanbon)

Please help! I have to solve these equations by elimination: #1 2x + 3y = 12 and y... (answered by jennywecas)

Solve the system: y=2x+1 and x^2 + y^2 =25. Do I do this with graphing or... (answered by stanbon)

Solve by substitution or elimination: 3x-4y+2z=-2 5x-y+3z=1... (answered by elima)

How do you solve 2y=5x-1 and x=y+2? (Solve by graphing) How do you solve x=5 and... (answered by Alan3354)

Solve by substitution method: (x+2)/5 = (y-1)/2 and (x-1)/2 - (2y+1)/3 = 1 How to... (answered by josgarithmetic,ikleyn)

please help me solve these equations using elimination y=(1/3)x+2 and y=(5/2)x-1 (answered by solver91311,stanbon)