SOLUTION: Write an equation of a line that passes through the point (9,-1) and is parallel to x+y=6. Write three different equations in standard form, point slope form, and slope-intercept f

Question 495581: Write an equation of a line that passes through the point (9,-1) and is parallel to x+y=6. Write three different equations in standard form, point slope form, and slope-intercept form.
Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
The line x+y = 6:
x + y = 6
y = -x + 6
So the slope, m, is -1.
The y-intercept, b, is 6
.
The desired line is parallel to the above line, passing through the point (9,-1).
So it will have a slope of -1 to be parallel.
When x = 9, y = -1
y = mx + b
-1 = -1(9) + b
-1 = -9 + b
b = 8
therefore, the equation that goes through (9,-1) and is parallel is:
y = -x + 8
.
In the following graph, the original equation is in red; the second equation is in green.

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