SOLUTION: i can't figure out the steps to find the zeros of this equation: y=125x^3-8

Question 483445: i can't figure out the steps to find the zeros of this equation: y=125x^3-8
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
figure out the steps to find the zeros of this equation: y=125x^3-8
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Solve: 125x^3-8 = 0
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(5x)^2-2^3 = 0
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Factor:
(5x-2)(25x^2+10x+4) = 0
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x = 2/5 and x is the zeroes of 25x^2+10x+4 = 0
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Solve: 25x^2+10x+4 = 0
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x = [-10 +- sqrt(100-4*25*4)]/50
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x = [-10 +- sqrt(-300)]/50
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x = [-10 +- 10sqrt(3)i]/50
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x = (-1/5)-(1/5)sqrt(3)i pr x = (-1/5)+(1/5)sqrt(3)i
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Note: There are 3 solutions
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Cheers,
Stan H.
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